MCQs on Dynamics of Charged Particles(Set-003)

Dynamics of Charged Particles

Quiz

 

1. The intensity of the electric field which will impart an acceleration equal to acceleration due to gravity to an alpha particle initially at rest
   1.   $20.46 \times 10^{-7} N/C $
   2.   $20.46 \times 10^{-8} N/C $
   3.   $20.46 \times 10^{-6} N/C $
   4.   $20.46 \times 10^{-9} N/C $
2. If a beam of charged particles moving with initiaol velocity of $7.5 \times 10^6 m/s$ , gets deflected by $4 mm$ in traversing a distance of 12 cm througfh an electrostatic field of $2.2 kV/m$ , perpendicular to their path, the specific charge of the particles would be
   1.   $227.2 \times 10^6 C/kg$
   2.   $227.2 \times 10^3 C/kg$
   3.   $227.2 C/kg$
   4.   None above
3. A helium nucleus was initially at rest. After being accelerated by a PD of 2.8kV,it passes through a region $AB$ of length 5 m with uniform velocity. The transit time required by the nucleus to traverse the length $AB$, must be
   1.   $ 1.93 \mu s$
   2.   $ 1.93 m s$
   3.   $ 1.93 n s $
   4.   $ 1.93 p s$
4. Two parallel plates are kept in air at 2 cm apart and a PD of 180 V is applied.An electron was resting initially on the plate at lower potential. The KE of the electron when it will reach the other plate, have to be
   1.   $1.79 \times 10^2 eV$
   2.   $1.79 \times 10^3 eV$
   3.   $1.79 \times 10^4eV$
   4.   $1.79 \times 10^5 eV$
5. A proton travelling with a velocity of $v_x= 6 \times 10^8 m /s $ enters in to a region of uniform magnetic field $\vec{B}= 3000 \hat{j}-1800 \hat{k}$ Gauss. It will experience a force of
   1.   $(28.8 \hat{i}+17.28 \hat{j}) \times 10^{-8} N$
   2.   $(28.8 \hat{i}-17.28 \hat{j}) \times 10^{-8} N$
   3.   $(28.8 \hat{k}-17.28 \hat{j}) \times 10^{-8} N$
   4.   $(28.8 \hat{k}+17.28 \hat{j}) \times 10^{-8} N$
6. An electron of velocity $v= (3 \hat{j}- 2 \hat{k}) \times 10^6 \ cm/s$ enters a region of uniform magnetic field , $B= 450 \hat{j} Gauss$. Its path inside the magnetic field would be
   1.   elliptical path
   2.   Circular path
   3.   helical path
   4.   Straight line inclined at an angle to the direction of the magnetic field
7. An electron has a velocity of $7.5 \times 10^5 m/s$ normal to a magnetic field of $2.5 Wm/m^2$. The frequency of revolution of the electron inside the magentic field, must be
   1.   $7.0004 \times 10^{7} \ \ rps$
   2.   $7.0004 \times 10^{8} \ \ rps$
   3.   $7.0004 \times 10^{19} \ \ rps$
   4.   $7.0004 \times 10^{10} \ \ rps$
8. A proton, after being projected towards a conductor at positive potential, can manage just only to strike the conductor at $+1500 V $ potential.The initial velocity of the proton must be
   1.   $54.77 \times 10^3 m/s$
   2.   $54.77 \times 10^4 m/s$
   3.   $54.77 \times 10^5 m/s$
   4.   $54.77 \times 10^6 m/s$
9. An electron of energy $25 eV$ moving in a direction perpendicular to a magnetic field of $B=120 Wb/m^2$, describes a circular path . The radius of the circular path would be
   1.   $0.140\times 10^{-5} m $
   2.   $0.140\times 10^{-6} m $
   3.   $0.140\times 10^{-7} m $
   4.   $0.140\times 10^{-8} m $
10. The electric field between the plates of a CRO is $1.8 \times 10^4 N/C$. The plates are 2 cm long.The deflection that an electron will experience if it enters at right angles to the field with a KE of 2.5KeV, will be
    1.   18 cm
    2.   1.8 cm
    3.   0.18 cm
    4.   0.018 cm

MCQs on Digital Electronics(Set-002)

Multiple Choice Questions on Digital Electronics

Quiz

 

1. The result of simplication of the logic expression $Y= AB+ \overline{AC}+ A\overline{B} C(AB+C)$ , is
   1.   0
   2.   1
   3.   A
   4.   $\overline{A}$
2. The Sum of Product (SOP) solution of a arbritrary logic function $Y= (A+BC)(B+ \overline{C}A)$ has to be
   1.   $\overline{C}B+ A \overline{C}+ BC$
   2.   $AB+ A C+ B\overline{C}$
   3.   $AB+ A \overline{C}+ BC$
   4.   None above
3. To implement the logic circuit for the expression $Y= A \overline{B} +AB+(\oveline{A}+B)(A+B)$, one requires
   1.   Only two 2 input OR gate
   2.   Only one 2 input OR gate
   3.   Less than 5 AND Gate and less than two OR gate
   4.   More than 5 AND gate and more than 2 OR gate
4. The decimal equivalent of the hexadecimal number $(ABCD)_16$ is
   1.   43981
   2.   39481
   3.   93481
   4.   34981
5. $\overline{A\overline{B}C}+ A\overline{B} \left( \overline{\overline{A} \overline{C}}\right) =?$
   1.   A
   2.   1
   3.   B
   4.   C
6. A three variable truth table has high output for the input conditions $000, 010, 100, 110$. To implement the SOP solution in a cost effective way, one requires
   1.   4 OR gates and 1 AND gate
   2.   5 NAND gates
   3.   4 AND gates and 1 OR gate
   4.   A NOT gate only
7. The simplified boolean expression for the K-map shown in figure 7 , must be
   1.   $Y= ABC+AC+AD+BD$
   2.   $Y= AB+AC+AD+BCD$
   3.   $Y= AB+ACD+AD+CD$
   4.   $Y= AB+AC+ABD+CD$
8. If $Y= (\overline{A}+\overline{B}) \overline{C}+ \overline{AB}+(\overline{AC}+B)(\overline{\overline{A}+\overline{C}})$, then the number of NAND gates required to implement this boolean function, will be
   1.   Total 4 NAND gate(3 single input NAND gate and one 3 input NAND gate)
   2.   Total 2 NAND gate(One single input NAND gate and one 3 input NAND gate)
   3.   Total 3 NAND gate(One single input NAND gate and two 2 input NAND gate)
   4.   None above
9. The Product of Sum (PoS) equivalent of the boolean expression $Y= (A+BC)(B+ \overline{C}A)$ has to be
   1.   $(A+B)(A+C)(B+ \overline{C})$
   2.   $(A+B)(A+C)(B+ C)$
   3.   $(A+B)(A+\overline{C})(B+ C)$
   4.   $(A+\overline{B})(A+C)(B+ C)$
10. The hexadecimal number $FACE$ and the binary number $1111101011001110$ are same
    1.   False
    2.   true
    3.   Cant say
    4.   None above